Coverage for hiphive/core/clusters.py: 100%
53 statements
« prev ^ index » next coverage.py v7.6.8, created at 2024-11-28 11:20 +0000
« prev ^ index » next coverage.py v7.6.8, created at 2024-11-28 11:20 +0000
1# Contains the get_clusters function which generates clusters
3import numpy as np
4import itertools
5from collections import defaultdict
7from .utilities import BiMap
8from ..input_output.logging_tools import logger
10logger = logger.getChild('get_clusters')
13# TODO: This function could be made a bit more general
14def get_clusters(atoms, cutoffs, nPrim, multiplicity=True,
15 use_geometrical_order=False):
16 """Generate a list of all clusters in the atoms object which includes the
17 center atoms with positions within the cell metric. The cutoff determines
18 up to which order and range clusters should be generated.
20 With multiplicity set to True clusters like `[0,0]` and `[3,3,4` etc will
21 be generated. This is useful when doing force constants but not so much for
22 cluster expansions.
24 The geometrical order is the total number of different atoms in the
25 cluster. `[0,0,1]` would have geometrical order 2 and `[1,2,3,4]` would
26 have order 4. If the key word is True the cutoff criteria will be based on
27 the geometrical order of the cluster. This is based on the observation that
28 many body interactions decrease fast with cutoff but anharmonic
29 interactions can be quite long ranged.
31 Parameters
32 ----------
33 atoms : ase.Atoms
34 can be a general atoms object but must have pbc=False.
35 cutoffs : dict
36 the keys specify the order while the values specify the cutoff radii
37 multiplicity : bool
38 includes clusters where same atom appears more than once
39 geometrical_order : bool
40 specifies if the geometrical order should be used as cutoff_order,
41 otherwise the normal order of the cluster is used
43 Returns
44 -------
45 list(tuple(int))
46 a list of clusters where each entry is a tuple of indices,
47 which refer to the atoms in the input supercell
48 """
50 logger.debug('Generating clusters...')
51 cluster_dict = defaultdict(list)
52 # Generate all on-site clusters of all orders (1-body)
53 for i in range(nPrim):
54 for order in cutoffs.orders:
55 cluster = (i,) * order
56 cluster_dict[order].append(cluster)
58 # Generate all 2-body clusters and above in order
59 for nbody in cutoffs.nbodies:
60 cutoff = cutoffs.max_nbody_cutoff(nbody)
61 # Generate all n-body, order n clusters compatible with the cutoff
62 nbody_clusters, nbody_cutoffs = generate_geometrical_clusters(atoms, nPrim, cutoff, nbody)
63 for order in range(nbody, cutoffs.max_nbody_order(nbody) + 1):
64 for cluster, cutoff in zip(nbody_clusters, nbody_cutoffs):
65 # If the cutoff of the n-body cluster is compatible with order (order > n) then
66 # extend the n-body cluster to higher order (e.g. nbody=3, order=6: ijk -> iijkkk)
67 if cutoff < cutoffs.get_cutoff(nbody=nbody, order=order):
68 cluster_dict[order].extend(extend_cluster(cluster, order))
70 # The clusters are saved in a BiMap structure which allows for fast lookups
71 cluster_list = BiMap()
72 for key in sorted(cluster_dict):
73 # For each order the clusters are saved in lexicographical order
74 for cluster in sorted(cluster_dict[key]):
75 cluster_list.append(cluster)
76 return cluster_list
79def generate_geometrical_clusters(atoms, n_prim, cutoff, order):
80 neighbor_matrix, distance_matrix = create_neighbor_matrices(atoms, cutoff)
81 clusters, cutoffs = [], []
82 i, j = 0, 0
83 # The clusters are generated in lexicographical order
84 for cluster in itertools.combinations(range(len(atoms)), r=order):
85 # If the first atom in the cluster has an index higher or equal to the number of atoms in
86 # the primitive cell then no upcoming cluster will have an atom in the primitive cell, thus
87 # we can break
88 if cluster[0] >= n_prim:
89 break
90 # if the last cluster failed on index i, j we start by checking this index again to speed
91 # things up
92 if not neighbor_matrix[cluster[i], cluster[j]]:
93 continue
94 # loop through all pairs in the cluster and check so that they are neighbors
95 for i, j in itertools.combinations(range(order), r=2):
96 if not neighbor_matrix[cluster[i], cluster[j]]:
97 break
98 else:
99 clusters.append(cluster)
100 # We also note the cutoff each cluster is compatible with
101 cutoffs.append(np.max(distance_matrix[cluster, :][:, cluster]))
102 return clusters, cutoffs
105def create_neighbor_matrices(atoms, cutoff):
106 distance_matrix = atoms.get_all_distances(mic=False) # or True?
107 neighbor_matrix = distance_matrix < cutoff
108 return neighbor_matrix, distance_matrix
111def extend_cluster(cluster, order):
112 clusters = []
113 cluster = tuple(cluster)
114 nbody = len(cluster)
115 r = order - nbody
116 for tup in itertools.combinations_with_replacement(cluster, r):
117 new_cluster = sorted(cluster + tup)
118 clusters.append(tuple(new_cluster))
119 return clusters